Which Light to use

you need to compare apples to apples using umol/s PAR production, not watts. efficacy x watts = umol/s PAR. use those numbers to determing the percentage of power to make them equivalent as far as light production. The frame with better diode distribution will be your best option. You could run both of them at lower levels, too... improve light distirbution, potentially, but some drivers lose efficiency below ~50% .. depends on the model in front of you. for 12 houroperation you want 80umol/s per sq ft -- that puts you near 37 DLI. 37 dli over 18hours is 2/3rds of that.. which is 53 1/3 umol/s per sq ft. Easy math from there... 80 x sq ft of tent = the amount of PAR produced from a light that you need for that tent. if one light produces enough, then it is enough. or, use both and a little more math to determing the pecent power to run both whil producing the calculated amount of PAR required for the tent. This "37" DLI is a good starting point for ambient CO2 levels. You will need to make small adjustments from there based on plant growth. There is no 1 answer for all in this regard as more than one factor adds up to what the maximum amount of light a plant can handle per day.