Yeah, the progress in either direction is what you want to in on.. if the damage stops or in the case of minor damage, reverses, you know you've corrected properly.
lights are generally designed to handle a 12hour schedule. So, when you use a grow light for autos and on a 18/6 schedule instead of 12/12, the use of the light should be based on their suggestions for vege phase. If they didn't give bad advice on the max flower area, it should be roughly 2/3rds of the vege area suggestion.
18/6 requires 67% power -- inversely proportional to change in hours of operation. 18h/12h or 3/2, which is 150% or 67% depending on which way you are going. Fewer hours obvioulsy needs a higher rate of photon production to provide the same amount of energy per day. This only applies when you cover the same area for vege and flower. With autoflowers, you don't need to worry about 12 hour needs. so you can either run the light at 67% and ~4sq ft coverage over 12h or 100% and 6 sq ft coverage over 18h.
I have an xs1500 - not a pro, but probably not a huge difference. Figure it can possibly cover about 6sq ft on an 18/6
@100% and stick closer to 4sq ft for 12 hour operation
@100%. Is that more or less than what it is currently focused on? That'll give a good idea of the power you need.
18-20" should be good enough to provide spread of light and not sacrifice overall DLI.
That's just for reference... and it's a ballpark, not an exact suggestion. if it's greatly off from what you were doing before, it gives you more evidence that it was caused by the light ... or not.
You only need ~600 ppfd over 18h for a good DLI. (again, needs adjustment based on plant growth due to local variables)
your light has a specification for umol/s PAR production - they may shorten it to umol/s or they may call it ppf or ppe. They may also lie, lol. Multiplying efficacy, if listed, by watts will also give the umol/s production of photons of the light.
divide that value by area in meters-squared, and that'll give you a rough PPFD estimate. 7sq ft / 10.76 sq ft = .65 m^2. Lit's say it;s 320 production. 320 / .65 = ~500ppfd. So, a 320 umol/s light would be okay for 7sq ft, but probably want ~20% more, ideally.
if you see the relationships, it's super easy to size a light... any light, given good specifications you can rely on.